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Physics-

General

Easy

Question

A plane mirror is placed at the bottom of a tank containing a liquid of refractive index m . P is a small object at a height h above the mirror. An observer O, vertically above P, outside the liquid, observes P and its image in the mirror. The apparent distance between these two will be

$2 μ h$
$\frac{2 h}{μ}$
$\frac{2 h}{μ - 1}$
$h (1 + \frac{1}{μ})$

The correct answer is: $fraction numerator 2 h over denominator mu end fraction$

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