Physics-
General
Easy

Question

A point object O is placed in front of a glass rod having spherical end of radius of curvature 30 cm. The image would be formed at

  1. 30 cm left    
  2. Infinity    
  3. 1 cm to the right    
  4. 18 cm to the left    

The correct answer is: 30 cm left


    By using formula fraction numerator mu subscript 2 end subscript over denominator v end fraction minus fraction numerator mu subscript 1 end subscript over denominator u end fraction equals fraction numerator mu subscript 2 end subscript minus mu subscript 1 end subscript over denominator R end fraction
    fraction numerator 1.5 over denominator v end fraction minus fraction numerator 1 over denominator left parenthesis negative 15 right parenthesis end fraction equals fraction numerator left parenthesis 1.5 minus 1 right parenthesis over denominator plus 30 end fraction rightwards double arrow v equals negative 30 c m.
    Negative sign shows that, image is obtained on the same side of object i.e. towards left.

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