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General
Easy

Question

A small block of mass M moves on a frictionless surface of an inclined plane, as shown in figure. The angle of the incline suddenly changes from 60 to the power of ring operator end exponent to 30 to the power of ring operator end exponent at point B. The block is initially at rest at A. Assume that collisions between the block and the incline are totally inelastic (g = 10 m divided by s to the power of 2 end exponent) The speed of the block at point B immediately after it strikes the second incline is :–

  1. square root of 60 m divided by s    
  2. square root of 45 m divided by s    
  3. square root of 30 m divided by s    
  4. square root of 15 m divided by s    

The correct answer is: square root of 30 m divided by s

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