Physics-
General
Easy

Question

A smooth ring of mass m can slides on a fixed horizontal rod. A string tied to the ring passes over a fixed pulley B and carries a block C of mass 2 m as shown below. As the ring starts sliding :

  1. The acceleration of the ring is fraction numerator 2 g c o s invisible function application q over denominator 1 plus 2 c o s to the power of 2 end exponent invisible function application q end fraction    
  2. The acceleration of the block is fraction numerator 2 g c o s to the power of 2 end exponent invisible function application q over denominator 1 plus 2 c o s to the power of 2 end exponent invisible function application q end fraction    
  3. The tension in the string is fraction numerator 2 m g over denominator 1 plus 2 c o s to the power of 2 end exponent invisible function application q end fraction    
  4. If the block descends with velocity v then the ring slides with velocity v c o s invisible function application q.    

The correct answer is: The acceleration of the block is fraction numerator 2 g c o s to the power of 2 end exponent invisible function application q over denominator 1 plus 2 c o s to the power of 2 end exponent invisible function application q end fraction

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