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Question

A spherical uniform planet is rotating about its axis. The velocity of a point on its equator is V. Due to the rotation of planet about its axis the acceleration due to gravity g at equator is 1/2 of g at poles. The escape velocity of a particle on the planet in terms of V.

  1. Ve = 2V    
  2. Ve = V    
  3. Ve = V/2    
  4. Ve = square root of 3V    

The correct answer is: Ve = 2V

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