Physics-
General
Easy

Question

A steel block of mass M is being lifted by a helicopter, which is accelerating upward with an acceleration of magnitude a. The block is attached to a horizontal bar by two cables, which make angles of theta subscript 1 end subscript and theta subscript 2 end subscript w.r.t. horizontal as shown in the figure. The tension in the cable 1 in terms of M, theta subscript 1 end subscript, theta subscript 2 end subscript, g and a is

  1. fraction numerator M left parenthesis g plus a right parenthesis c o s invisible function application theta subscript 1 end subscript over denominator sin invisible function application open parentheses theta subscript 1 end subscript plus theta subscript 2 end subscript close parentheses end fraction    
  2. fraction numerator M left parenthesis g plus a right parenthesis s i n invisible function application theta subscript 1 end subscript over denominator cos invisible function application open parentheses theta subscript 1 end subscript plus theta subscript 2 end subscript close parentheses end fraction    
  3. fraction numerator M left parenthesis g plus a right parenthesis s i n invisible function application theta subscript 2 end subscript over denominator cos invisible function application open parentheses theta subscript 1 end subscript plus theta subscript 2 end subscript close parentheses end fraction    
  4. fraction numerator M left parenthesis g plus a right parenthesis c o s invisible function application theta subscript 2 end subscript over denominator sin invisible function application open parentheses theta subscript 1 end subscript plus theta subscript 2 end subscript close parentheses end fraction    

The correct answer is: fraction numerator M left parenthesis g plus a right parenthesis c o s invisible function application theta subscript 2 end subscript over denominator sin invisible function application open parentheses theta subscript 1 end subscript plus theta subscript 2 end subscript close parentheses end fraction

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