Physics-
General
Easy

Question

A thermodynamic process is shown in the figure. The pressures and volumes corresponding to some points in the figure are : P subscript A end subscript equals 3 cross times 1 0 to the power of 4 end exponent P a comma   P subscript B end subscript equals 8 cross times 1 0 to the power of 4 end exponent P a and V subscript A end subscript equals 2 cross times 1 0 to the power of negative 3 end exponent m to the power of 3 end exponent comma   V subscript D end subscript equals 5 cross times 1 0 to the power of negative 3 end exponent m to the power of 3 end exponent
In process AB, 600 J of heat is added to the system and in process BC, 200 J of heat is added to the system. The change in internal energy of the system in process AC would be

  1. 560 J    
  2. 800 J    
  3. 600 J    
  4. 640 J    

The correct answer is: 560 J


    By adjoining graph W subscript A B end subscript equals 0 and
    W subscript B C end subscript equals 8 cross times 1 0 to the power of 4 end exponent left square bracket 5 minus 2 right square bracket cross times 1 0 to the power of negative 3 end exponent equals 240 J
    \ W subscript A C end subscript equals W subscript A B end subscript plus W subscript B C end subscript equals 0 plus 240 equals 240 J
    Now, capital delta Q subscript A C end subscript equals capital delta Q subscript A B end subscript plus capital delta Q subscript B C end subscript equals 600 plus 200 equals 800 J
    From FLOT capital delta Q subscript A C end subscript equals capital delta U subscript A C end subscript plus capital delta W subscript A C end subscript
    Þ 800 equals capital delta U subscript A C end subscript plus 240 Þ capital delta U subscript A C end subscript equals 560 J.

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