Physics-
General
Easy

Question

A thin wire of length L and uniform linear mass density rho is bent into a circular loop with centre at O as shown. The moment of inertia of the loop about the axis XX’ is:

  1. rho L to the power of 3 end exponent divided by 8 pi to the power of 2 end exponent    
  2. rho L to the power of 3 end exponent divided by 16 pi to the power of 2 end exponent    
  3. 5 rho L to the power of 3 end exponent divided by 16 pi to the power of 2 end exponent    
  4. 3 p L to the power of 3 end exponent divided by 8 pi to the power of 2 end exponent    

The correct answer is: rho L to the power of 3 end exponent divided by 16 pi to the power of 2 end exponent

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