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Physics-

General

Easy

Question

A transparent solid cylindrical rod has a refractive index of $2 divided by square root of 3$ . It is surrounded by air. A light ray is incident at the midpoint of one end of the rod as shown in the figure The incident angle $theta$ for which the light ray grazes along the wall of the rod is

${s i n}^{- 1} (\frac{\sqrt{3}}{2})$
${s i n}^{- 1} (\frac{2}{\sqrt{3}})$
${s i n}^{- 1} (\frac{1}{\sqrt{3}})$
${s i n}^{- 1} (\frac{1}{2})$

The correct answer is: $s i n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator square root of 3 end fraction close parentheses$

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