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A uniform rod of mass m suspended by two identical threads l in length (see figure) was turned through a small angle about the vertical axis passing through its middle point C. The threads deviated in the process through a small angle Then the rod was released to start performing small oscillations. The rod's oscillation energy is

  1. m g l alpha to the power of 2 end exponent divided by 2    
  2. m g l alpha to the power of 2 end exponent    
  3. m g l alpha to the power of 2 end exponent divided by 12    
  4. not possible to find since rod length is not given    

The correct answer is: m g l alpha to the power of 2 end exponent

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