Physics-
General
Easy

Question

An inductor (L = 100 mH), a resistor (R = 100 capital omega) and a battery (E = 100 V) are initially connected in series as shown in the figure. After a long time the battery is disconnected after short circuiting the points A and B. The current in the circuit, 1 ms after the short circuit is:

  1. 1 A    
  2. 1/e A    
  3. e A    
  4. 0.1 A    

The correct answer is: 1/e A


    I equals I subscript 0 end subscript e to the power of negative R u L end exponent equals fraction numerator 1 over denominator e end fraction A

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