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Physics-

General

Easy

Question

As per given future to complete the circular loop what should be the radius if initial height is $5 blank m$

$4 m$
$3 m$
$2.5 m$
$2 m$

The correct answer is: $2 blank m$

$h equals fraction numerator 5 over denominator 2 end fraction r rightwards double arrow r equals fraction numerator 2 over denominator 5 end fraction cross times h equals fraction numerator 2 over denominator 5 end fraction cross times 5 equals 2 blank m e t r e$

Related Questions to study

Figure shows four paths for a kicked football. Ignoring the effects of air on the flight, rank the paths according to initial horizontal velocity component, highest first

Figure shows four paths for a kicked football. Ignoring the effects of air on the flight, rank the paths according to initial horizontal velocity component, highest first

physics-General

The area of the region bounded by $blank y equals open vertical bar x minus 1 close vertical bar blank$ and y=1 in sq. units is

The area of the region bounded by $blank y equals open vertical bar x minus 1 close vertical bar blank$ and y=1 in sq. units is

Area of the region bounded by $blank y equals open vertical bar x close vertical bar blank$ and y=2 is

Area of the region bounded by $blank y equals open vertical bar x close vertical bar blank$ and y=2 is

parallel

The area bounded by $blank y equals c o s blank x comma blank y equals x plus 1 blank$ and y=0 in the second quadrant is

The area bounded by $blank y equals c o s blank x comma blank y equals x plus 1 blank$ and y=0 in the second quadrant is

The area bounded by the two curves $blank y equals square root of x blank a n d blank x equals square root of y blank$ is

The area bounded by the two curves $blank y equals square root of x blank a n d blank x equals square root of y blank$ is

The area bounded by y = $blank s i n x blank$ in [0,2 $pi$ ]

The area bounded by y = $blank s i n x blank$ in [0,2 $pi$ ]

parallel

The area bounded by curve $blank y equals s i n blank x comma blank x minus a x i s blank$ and the ordinates x=0 and $blank x equals fraction numerator pi over denominator 2 end fraction$ is

The area bounded by curve $blank y equals s i n blank x comma blank x minus a x i s blank$ and the ordinates x=0 and $blank x equals fraction numerator pi over denominator 2 end fraction$ is

The area bounded by the parabola $blank y to the power of 2 end exponent equals 4 x blank$ and the line 2x-3y+4=0, in square units, is

The area bounded by the parabola $blank y to the power of 2 end exponent equals 4 x blank$ and the line 2x-3y+4=0, in square units, is

The area (in square units)bounded by the curves y= $square root of x comma blank 2 y minus x plus 3 equals 0 comma blank x minus$ a x is, and lying in the first quadrant is

The area (in square units)bounded by the curves y= $square root of x comma blank 2 y minus x plus 3 equals 0 comma blank x minus$ a x is, and lying in the first quadrant is

parallel

The area under the curve y= $open vertical bar c o s blank x minus s i n blank x close vertical bar comma 0 less or equal than x less or equal than fraction numerator pi over denominator 2 end fraction comma$ and above x-axis is:

The area under the curve y= $open vertical bar c o s blank x minus s i n blank x close vertical bar comma 0 less or equal than x less or equal than fraction numerator pi over denominator 2 end fraction comma$ and above x-axis is:

The area of the region (in sq. units), in the first quadrant, bounded by the parabola y= $9 x to the power of 2 end exponent blank$ and the lines x=0,y=1 and y=4 is:

The area of the region (in sq. units), in the first quadrant, bounded by the parabola y= $9 x to the power of 2 end exponent blank$ and the lines x=0,y=1 and y=4 is:

The area bounded by the curve y=ln (x) and the lines y=0, y=ln(3) and x=0 is equal to:

The area bounded by the curve y=ln (x) and the lines y=0, y=ln(3) and x=0 is equal to:

parallel

Let A= $open curly brackets open parentheses x comma y close parentheses colon y to the power of 2 end exponent less or equal than 4 x comma blank y minus 2 x greater or equal than negative 4 close curly brackets$ The area (in square units) of the region A is:

Let A= $open curly brackets open parentheses x comma y close parentheses colon y to the power of 2 end exponent less or equal than 4 x comma blank y minus 2 x greater or equal than negative 4 close curly brackets$ The area (in square units) of the region A is:

The area (in sq units) of the region bounded by the curves $blank y plus 2 x to the power of 2 end exponent equals 0 blank$ and $blank y plus 3 x to the power of 2 end exponent equals 1 blank$ is

The area (in sq units) of the region bounded by the curves $blank y plus 2 x to the power of 2 end exponent equals 0 blank$ and $blank y plus 3 x to the power of 2 end exponent equals 1 blank$ is

The area between the parabolas $blank y to the power of 2 end exponent equals$ 4a(x+a) and
$y to the power of 2 end exponent$ =-4a(x-a)in sQ units….

The area between the parabolas $blank y to the power of 2 end exponent equals$ 4a(x+a) and
$y to the power of 2 end exponent$ =-4a(x-a)in sQ units….

parallel

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