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Physics-

General

Easy

Question

For the circuit shown in the figure the rms value of voltages across R and coil are E₁ and E₂ , respectively

The power (thermal) developed across the coil is

$\frac{E - E_{1}^{2}}{2 R}$
$\frac{E - E_{1}^{2} - E_{2}^{2}}{2 R}$
$\frac{E^{2}}{2 R}$
$\frac{{(E - E_{1})}^{2}}{2 R}$

The correct answer is: $fraction numerator E minus E subscript 1 end subscript superscript 2 end superscript minus E subscript 2 end subscript superscript 2 end superscript over denominator 2 R end fraction$

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Find out V,K,B:

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