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Physics-

General

Easy

Question

If a charged particle of charge to mass ratio $q divided by m equals alpha$ is entering in a magnetic field of strength B at a speed $v equals left parenthesis 2 alpha d right parenthesis left parenthesis B right parenthesis$ , then which of the following is correct?

Angle subtended by charged particle at the centre of circular path is $2 π$ .
The charge will move on a circular path and will come out from magnetic field at a distance 4d from the point of insertion
The time for which particle will be in the magnetic field is $\frac{2 π}{α B}$
The charged particle will subtend an angle of 90° at the centre of circular path

The correct answer is: The charge will move on a circular path and will come out from magnetic field at a distance 4d from the point of insertion

$R equals fraction numerator m v over denominator Q b end fraction equals fraction numerator v over denominator alpha B end fraction equals 2 d$

Angle substended at the centre = p
Time to stay in magnetic field $blank equals fraction numerator T over denominator 2 end fraction equals fraction numerator pi over denominator alpha B end fraction$

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