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Physics-

General

Easy

Question

In the arrangement shown in figure $m subscript A end subscript equals m subscript B end subscript equals 2 k g.$ String is massless and pulley is frictionless. Block B is resting on a smooth horizontal surface, while friction coefficient between blocks A and B is $mu equals 0.5.$ The maximum horizontal force F can be applied so that blocks A does not slip over the blocks B is $open parentheses g equals 10 m divided by s to the power of 2 end exponent close parentheses$

25 N
40 N
30 N
20 N

The correct answer is: 20 N

Related Questions to study

Blocks A and B in the figure are connected by a bar of negligible weight. If mass of A and B are 170 kg each and $mu subscript A end subscript equals 0.2$ and $mu subscript B end subscript equals 0.4 comma$ where $mu subscript A end subscript$ and $mu subscript B end subscript$ are the coefficient of limiting friction between blocks and plane, calculate the force in the bar. $open parentheses g equals 10 m divided by s to the power of 2 end exponent close parentheses$

Blocks A and B in the figure are connected by a bar of negligible weight. If mass of A and B are 170 kg each and $mu subscript A end subscript equals 0.2$ and $mu subscript B end subscript equals 0.4 comma$ where $mu subscript A end subscript$ and $mu subscript B end subscript$ are the coefficient of limiting friction between blocks and plane, calculate the force in the bar. $open parentheses g equals 10 m divided by s to the power of 2 end exponent close parentheses$

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