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Physics-

General

Easy

Question

In the circuit shown, the internal resistance of the cell is negligible. The steady state current in the 2 $blank capital omega$ resistance is

0.6A
1.2A
0.9A
1.5A

The correct answer is: 0.9A

In the steady state, no current flows through the branch containing the capacitor. So, the equivalent circuit will be of the form as shown below:

The effective resistance of the circuit is
$R equals fraction numerator 2 cross times 3 over denominator 2 plus 3 end fraction plus 2.8 equals 1.2 plus 2.8 equals 4 capital omega$
The current through the circuit is

$i equals fraction numerator E over denominator R end fraction equals fraction numerator 6 over denominator 4 end fraction equals 1.5 A$
Let current $i subscript 1 end subscript$ flows through 2 $capital omega$ resistance.
$therefore blank 2 cross times i subscript 1 end subscript equals open parentheses i minus i subscript 1 end subscript close parentheses cross times 3$
$⟹ blank 2 i subscript 1 end subscript equals open parentheses 1.5 minus i subscript 1 end subscript close parentheses cross times 3$
$⟹ 2 i subscript 1 end subscript equals 4.5 minus 3 i subscript 1 end subscript$
$⟹ 5 i subscript 1 end subscript equals 4.5$
$⟹ i subscript 1 end subscript equals 0.9 A$

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