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Physics-

General

Easy

Question

In the figure shown a thin parallel beam of light is incident on a plane mirror $m subscript 1 end subscript$ at small angle $blank to the power of ´ end exponent theta to the power of ´ end exponent$ . $m subscript 2 end subscript$ is a concave mirror of focal length ‘f’. After three successive reflections of this beam the x and y coordinates of the image is

$x = f - d, y = f θ$
$x = d + f, y = f θ$
$x = f - d, y = - f θ$
$x = d - f, y = - f θ$

The correct answer is: $x equals d minus f comma y equals negative f theta$

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