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General
Easy

Question

In the figure shown fraction numerator sin invisible function application i over denominator sin invisible function application r end fraction is equal to

  1. fraction numerator mu subscript 2 end subscript superscript 2 end superscript over denominator mu subscript 3 end subscript mu subscript 1 end subscript end fraction    
  2. fraction numerator mu subscript 3 end subscript over denominator mu subscript 1 end subscript end fraction    
  3. fraction numerator mu subscript 3 end subscript mu subscript 1 end subscript over denominator mu subscript 2 end subscript superscript 2 end superscript end fraction    
  4. none    

The correct answer is: fraction numerator mu subscript 3 end subscript over denominator mu subscript 1 end subscript end fraction

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