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Physics-

General

Easy

Question

In the figure shown the electric potential energy of the system is (q is at the centre of the conducting neutral spherical shell of inner radius a and outer radius b)

0
$\frac{{k q}^{2}}{2 b}$
$\frac{{k q}^{2}}{2 b} - \frac{k q^{2}}{2 a}$
$\frac{{k q}^{2}}{2 a} - \frac{{k q}^{2}}{2 b}$

The correct answer is: $fraction numerator k q to the power of 2 end exponent over denominator 2 b end fraction minus fraction numerator k q to the power of 2 end exponent over denominator 2 a end fraction$

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