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Physics-

General

Easy

Question

One end of a copper rod of length $1.0 m$ and area of cross-section $1 0 to the power of negative 3 end exponent$ is immersed in boiling water and the other end in ice. If the coefficient of thermal conductivity of copper is 92 cal/m-s-^oC and the latent heat of ice is $8 cross times 1 0 to the power of 4 end exponent c a l divided by k g$ , then the amount of ice which will melt in one minute is

$9.2 \times 1 0^{- 3} k g$
$8 \times 1 0^{- 3} k g$
$6.9 \times 1 0^{- 3} k g$
$5.4 \times 1 0^{- 3} k g$

The correct answer is: $6.9 cross times 1 0 to the power of negative 3 end exponent k g$

Heat transferred in one minute is utilised in melting the ice so, $fraction numerator K A left parenthesis theta subscript 1 end subscript minus theta subscript 2 end subscript right parenthesis t over denominator l end fraction equals m cross times L$
$rightwards double arrow m equals fraction numerator 1 0 to the power of negative 3 end exponent cross times 92 cross times open parentheses 100 minus 0 close parentheses cross times 60 over denominator 1 cross times 8 cross times 1 0 to the power of 4 end exponent end fraction equals 6.9 cross times 1 0 to the power of negative 3 end exponent k g$

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