Physics-
General
Easy

Question

Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth, is [g is acceleration due to gravity at Earth’s surface]

  1. 2 pi square root of fraction numerator 2 R over denominator g end fraction end root    
  2. 4 square root of 2 pi end root square root of fraction numerator R over denominator g end fraction end root    
  3. 2 pi square root of fraction numerator R over denominator g end fraction end root    
  4. 8 pi square root of fraction numerator R over denominator g end fraction end root    

The correct answer is: 4 square root of 2 pi end root square root of fraction numerator R over denominator g end fraction end root

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