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Physics-

General

Easy

Question

The charge on the capacitor of capacitance $C$ shown in the figure below will be

$C E$
$\frac{C E R_{1}}{R_{1} + r}$
$\frac{C E R_{2}}{R_{2} + r}$
$\frac{C E R_{2}}{R_{1} + r}$

The correct answer is: $fraction numerator C E R subscript 2 end subscript over denominator R subscript 2 end subscript plus r end fraction$

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