Physics-
General
Easy

Question

The given lens is broken into four parts and rearranged as shown in the figure. If the initial focal length is f then after rearrangement the equivalent focal length is

  1. f    
  2. fraction numerator f over denominator S 2 end fraction    
  3. fraction numerator f over denominator 4 end fraction    
  4. 4f    

The correct answer is: fraction numerator f over denominator S 2 end fraction


    Cutting a lens in transverse direction doubles their focal length i.e. 2f.
    Using the formula of equivalent focal length
    fraction numerator 1 over denominator f end fraction equals fraction numerator 1 over denominator f subscript 1 end subscript end fraction plus fraction numerator 1 over denominator f subscript 2 end subscript end fraction plus fraction numerator 1 over denominator f subscript 3 end subscript end fraction plus fraction numerator 1 over denominator f subscript 4 end subscript end fraction
    We get equivalent focal length as fraction numerator f over denominator 2 end fraction

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