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Physics-

General

Easy

Question

The graph. Shown in the adjacent diagram, represents the variation of temperature (T) of two bodies, x and y having same surface area, with time (t) due to the emission of radiation. Find the correct relation between the emissivity (e) and absorptivity (a) of the two bodies

$e_{x} > e_{y} & a_{x} < a_{y}$
$e_{x} < e_{y} & a_{x} > a_{y}$
$e_{x} > e_{y} & a_{x} > a_{y}$
$e_{x} < e_{y} & a_{x} < a_{y}$

The correct answer is: $e subscript x end subscript greater than e subscript y end subscript & a subscript x end subscript greater than a subscript y end subscript$

Rate of cooling $open parentheses negative fraction numerator d T over denominator d t end fraction close parentheses proportional to$ emissivity (e)
From graph, $open parentheses negative fraction numerator d T over denominator d t end fraction close parentheses subscript x end subscript greater than open parentheses negative fraction numerator d T over denominator d t end fraction close parentheses subscript y end subscript$ Þ $e subscript x end subscript greater than e subscript y end subscript$
Further emissivity (e) µ Absorptive power (a) Þ $a subscript x end subscript greater than a subscript y end subscript$
( $because$ good absorbers are good emitters)

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