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Physics-

General

Easy

Question

Three particles, each of mass m are situated at the vertices of an equilateral triangle ABC of side $lambda$ cm (as shown in the figure). The moment of inertia of the system about a line AX perpendicular to AB and in the plane of ABC, in gram $c m to the power of 2 end exponent$ units will be :

$2 m l^{2}$
$\frac{5}{4} m l^{2}$
$\frac{3}{2} m l^{2}$
$\frac{3}{4} m S l^{2}$

The correct answer is: $fraction numerator 5 over denominator 4 end fraction m l to the power of 2 end exponent$

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