Physics-
General
Easy

Question

Two identical capacitors 1 and 2 are connected in series. The capacitor 2 contains a dielectric slab of constant K as shown. They are connected to a battery of emf V0 volts. The dielectric slab is then removed. Let Q1 and Q2 be the charge stored in the capacitors before removing the slab and Q1 ¢, and Q2 ¢ be the values after removing the slab. Then

  1. fraction numerator Q subscript 1 end subscript superscript plus end superscript over denominator Q subscript 1 end subscript end fraction equals open parentheses fraction numerator K plus 1 over denominator K end fraction close parentheses    
  2. fraction numerator Q subscript 2 end subscript superscript ' end superscript over denominator Q subscript 2 end subscript end fraction equals fraction numerator left parenthesis K plus 1 right parenthesis over denominator 2 end fractionQ2=(K+1)2'/>    
  3. fraction numerator Q subscript 2 end subscript superscript ' end superscript over denominator Q subscript 2 end subscript end fraction equals fraction numerator K plus 1 over denominator 2 K end fractionQ2=K+12K'/>    
  4. fraction numerator Q subscript 1 end subscript superscript ' end superscript over denominator Q subscript l end subscript end fraction equals fraction numerator K over denominator 2 end fractionQl=K2'/>    

The correct answer is: fraction numerator Q subscript 2 end subscript superscript ´ end superscript over denominator Q subscript 2 end subscript end fraction equals fraction numerator K plus 1 over denominator 2 K end fraction

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