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Physics-

General

Easy

Question

What is the relation between speeds of points A and B in the given figure.

$V_{B} = \frac{V (1 + s i n q)}{2 c o s q}$
$V_{B} = \frac{V (1 - s i n q)}{c o s q}$
$V_{B} = \frac{V (2 + s i n q)}{c o t q}$
$V_{B} = \frac{V (2 - c o s q)}{s i n q}$

The correct answer is: $V subscript B end subscript equals fraction numerator V left parenthesis 1 minus s i n invisible function application q right parenthesis over denominator c o s invisible function application q end fraction$

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