Physics-
General
Easy
Question
When an ammeter of negligible internal resistance is inserted in series with circuit it reads 1A. When the voltmeter of very large resistance is connected across X it reads 1V. When the point A and B are shorted by a conducting wire, the voltmeter measures 10 V across the battery. The internal resistance of the battery is equal to
- zero
- 0.5
- 0.2
- 0.1
The correct answer is: 0.2
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