Maths-
General
Easy

Question

Prove that square root of 5 is an irrational number.

The correct answer is: Yes, it's an irrational number


    Hint:
    The real numbers which cannot be expressed in the form of p/q(where p and q are integers and q ≠ 0) are known as irrational numbers. In the given question we are asked to prove if   is irrational number. To do so we use the method of contradiction.
    Solution
    Let's assume that  is a rational number.
    Step 1 of 2:
    If  is rational, that means it can be written in the form of p/q, where p and q integers that have no common factor other than 1 i.e. they are coprime than 1 and q ≠ 0.

    So,fraction numerator square root of 5 over denominator 1 end fraction equals p over q

    square root of 5q = p

    Squaring both sides,

    5q= p2

    q2=p squared over 5
    This means p2  can be divided by 5
    Step 2 of 2:
    So if p2 can be divided by 5, then p can also be divided by 5

      So, let’s sayp over 5 equals r

    p=5r

    Squaring both sides

    p squared equals 25 r squared

    Putting the value of p2 in eq-1

    5 q squared equals 25 r squared

    q squared equals 5 r squared

    q squared over 5 equals r squared

    So, this means q² is divisible by 5 and so q is also divisible by 5.
    Final Answer: p and q both are divisible 5 but we assumed that p and q are coprime and this contradiction has arisen because of our incorrect assumption that square root of 5  is a rational number. So, we conclude that square root of 5 is an irrational number.

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