Solution for the question - range of the function f(x)=(x^(2)+x+2)/(x^(2)+x+1);x in r is (1,7,5) '/> [1,7//3] '/> (1,11//7) '/> (1,oo) '/>

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Range of the function $f left parenthesis x right parenthesis equals fraction numerator x squared plus x plus 2 over denominator x squared plus x plus 1 end fraction semicolon x element of R text is end text$

$(1, \infty)$
$(1, 11 / 7)$
$[1, 7 / 3]$
$(1, 7 / 5)$

The correct answer is: $left square bracket 1 comma 7 divided by 3 right square bracket$

For domain of $sin to the power of negative 1 end exponent invisible function application open parentheses log subscript 3 invisible function application x close parentheses$
$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell negative 1 less or equal than log subscript 3 invisible function application x less or equal than 1 end cell row cell not stretchy rightwards double arrow 3 to the power of negative 1 end exponent less or equal than x less or equal than 3 end cell end table$
$therefore text Domain of end text sin to the power of negative 1 end exponent invisible function application open parentheses log subscript 3 invisible function application x close parentheses text is end text open square brackets 1 third comma 3 close square brackets text . end text$

The domain of $sin to the power of negative 1 end exponent invisible function application open parentheses log subscript 3 invisible function application x close parentheses text is end text$

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The domain of the function $f left parenthesis x right parenthesis equals log subscript 3 plus x end subscript invisible function application open parentheses x squared minus 1 close parentheses text is end text$

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If $f left parenthesis x right parenthesis equals 2 x to the power of 6 plus 3 x to the power of 4 plus 4 x squared$ , then $f to the power of straight prime left parenthesis x right parenthesis$ is

Differentiation is the process of determining a function's derivative. The derivative is the rate at which x changes in relation to y when x and y are two variables. A constant function has zero derivatives. For instance, f'(x) = 0 if f(x) = 8. So the derivative function is odd.

If $f left parenthesis x right parenthesis equals 2 x to the power of 6 plus 3 x to the power of 4 plus 4 x squared$ , then $f to the power of straight prime left parenthesis x right parenthesis$ is

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The domain of the function $f left parenthesis x right parenthesis equals log subscript 2 invisible function application open parentheses log subscript 3 invisible function application open parentheses log subscript 4 invisible function application x close parentheses close parentheses$ is

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$text If end text f left parenthesis x right parenthesis equals fraction numerator 1 over denominator square root of vertical line x vertical line minus x end root end fraction text then, domain of end text f left parenthesis x right parenthesis text is end text$

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The domain of the function $f left parenthesis x right parenthesis equals exp invisible function application open parentheses square root of 5 x minus 3 minus 2 x squared end root close parentheses$ is

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The value of $tan invisible function application open curly brackets cos to the power of negative 1 end exponent invisible function application open parentheses negative 2 over 7 close parentheses minus pi over 2 close curly brackets$ is

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$sin invisible function application open parentheses 1 half cos to the power of negative 1 end exponent invisible function application 4 over 5 close parentheses$ is equal to

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If $a greater than b greater than 0$ , then the value of $tan to the power of negative 1 end exponent invisible function application open parentheses a over b close parentheses plus tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator a plus b over denominator a minus b end fraction close parentheses$ depends on

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$cot to the power of negative 1 end exponent invisible function application left parenthesis square root of cos invisible function application alpha end root right parenthesis minus tan to the power of negative 1 end exponent invisible function application left parenthesis square root of cos invisible function application alpha end root right parenthesis equals x$ then is equal to

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Number of solutions of the equation $tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator 2 x plus 1 end fraction close parentheses plus tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator 4 x plus 1 end fraction close parentheses equals tan to the power of negative 1 end exponent invisible function application open parentheses 2 over x squared close parentheses$ is

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$text If end text sec to the power of negative 1 end exponent invisible function application square root of 1 plus x squared end root plus cosec to the power of negative 1 end exponent invisible function application fraction numerator square root of 1 plus y squared end root over denominator y end fraction plus cot to the power of negative 1 end exponent invisible function application 1 over z equals pi$ $text then end text x plus y plus z$ is equal to

maths-General

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$cos invisible function application open square brackets cos to the power of negative 1 end exponent invisible function application open parentheses negative 1 over 7 close parentheses plus sin to the power of negative 1 end exponent invisible function application open parentheses negative 1 over 7 close parentheses close square brackets text is equal to end text$

maths-General

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$tan to the power of negative 1 end exponent invisible function application fraction numerator x over denominator square root of a squared minus x squared end root end fraction$ is equal to

maths-General

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If $theta equals sin to the power of negative 1 end exponent invisible function application x plus cos to the power of negative 1 end exponent invisible function application x minus tan to the power of negative 1 end exponent invisible function application x comma 1 less or equal than x less than straight infinity$ , then the smallest interval in which θ lies is

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Range of the function $f left parenthesis x right parenthesis equals fraction numerator x squared plus x plus 2 over denominator x squared plus x plus 1 end fraction semicolon x element of R text is end text$

$(1, \infty)$
$(1, 11 / 7)$
$[1, 7 / 3]$
$(1, 7 / 5)$

The correct answer is: $left square bracket 1 comma 7 divided by 3 right square bracket$

Related Questions to study

The domain of $sin to the power of negative 1 end exponent invisible function application open parentheses log subscript 3 invisible function application x close parentheses text is end text$

The domain of $sin to the power of negative 1 end exponent invisible function application open parentheses log subscript 3 invisible function application x close parentheses text is end text$

The domain of the function $f left parenthesis x right parenthesis equals log subscript 3 plus x end subscript invisible function application open parentheses x squared minus 1 close parentheses text is end text$

The domain of the function $f left parenthesis x right parenthesis equals log subscript 3 plus x end subscript invisible function application open parentheses x squared minus 1 close parentheses text is end text$

If $f left parenthesis x right parenthesis equals 2 x to the power of 6 plus 3 x to the power of 4 plus 4 x squared$ , then $f to the power of straight prime left parenthesis x right parenthesis$ is

If $f left parenthesis x right parenthesis equals 2 x to the power of 6 plus 3 x to the power of 4 plus 4 x squared$ , then $f to the power of straight prime left parenthesis x right parenthesis$ is

The domain of the function $f left parenthesis x right parenthesis equals log subscript 2 invisible function application open parentheses log subscript 3 invisible function application open parentheses log subscript 4 invisible function application x close parentheses close parentheses$ is

The domain of the function $f left parenthesis x right parenthesis equals log subscript 2 invisible function application open parentheses log subscript 3 invisible function application open parentheses log subscript 4 invisible function application x close parentheses close parentheses$ is

$text If end text f left parenthesis x right parenthesis equals fraction numerator 1 over denominator square root of vertical line x vertical line minus x end root end fraction text then, domain of end text f left parenthesis x right parenthesis text is end text$

$text If end text f left parenthesis x right parenthesis equals fraction numerator 1 over denominator square root of vertical line x vertical line minus x end root end fraction text then, domain of end text f left parenthesis x right parenthesis text is end text$

The domain of the function $f left parenthesis x right parenthesis equals exp invisible function application open parentheses square root of 5 x minus 3 minus 2 x squared end root close parentheses$ is

The domain of the function $f left parenthesis x right parenthesis equals exp invisible function application open parentheses square root of 5 x minus 3 minus 2 x squared end root close parentheses$ is

The value of $tan invisible function application open curly brackets cos to the power of negative 1 end exponent invisible function application open parentheses negative 2 over 7 close parentheses minus pi over 2 close curly brackets$ is

The value of $tan invisible function application open curly brackets cos to the power of negative 1 end exponent invisible function application open parentheses negative 2 over 7 close parentheses minus pi over 2 close curly brackets$ is

$sin invisible function application open parentheses 1 half cos to the power of negative 1 end exponent invisible function application 4 over 5 close parentheses$ is equal to

$sin invisible function application open parentheses 1 half cos to the power of negative 1 end exponent invisible function application 4 over 5 close parentheses$ is equal to

$tan to the power of negative 1 end exponent invisible function application fraction numerator x over denominator square root of a squared minus x squared end root end fraction$ is equal to

$tan to the power of negative 1 end exponent invisible function application fraction numerator x over denominator square root of a squared minus x squared end root end fraction$ is equal to

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Range of the function

The correct answer is:

For domain of

Related Questions to study

The domain of

The domain of

The domain of the function

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If , then is

If , then is

The domain of the function is

The domain of the function is

The domain of the function is

The domain of the function is

The value of is

The value of is

is equal to

is equal to

If , then the value of depends on

If , then the value of depends on

then is equal to

then is equal to

Number of solutions of the equation is

Number of solutions of the equation is

is equal to

is equal to

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is equal to

If , then the smallest interval in which θ lies is

If , then the smallest interval in which θ lies is

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Range of the function $f left parenthesis x right parenthesis equals fraction numerator x squared plus x plus 2 over denominator x squared plus x plus 1 end fraction semicolon x element of R text is end text$

The correct answer is: $left square bracket 1 comma 7 divided by 3 right square bracket$

The domain of $sin to the power of negative 1 end exponent invisible function application open parentheses log subscript 3 invisible function application x close parentheses text is end text$

The domain of $sin to the power of negative 1 end exponent invisible function application open parentheses log subscript 3 invisible function application x close parentheses text is end text$

The domain of the function $f left parenthesis x right parenthesis equals log subscript 3 plus x end subscript invisible function application open parentheses x squared minus 1 close parentheses text is end text$

The domain of the function $f left parenthesis x right parenthesis equals log subscript 3 plus x end subscript invisible function application open parentheses x squared minus 1 close parentheses text is end text$

If $f left parenthesis x right parenthesis equals 2 x to the power of 6 plus 3 x to the power of 4 plus 4 x squared$ , then $f to the power of straight prime left parenthesis x right parenthesis$ is

If $f left parenthesis x right parenthesis equals 2 x to the power of 6 plus 3 x to the power of 4 plus 4 x squared$ , then $f to the power of straight prime left parenthesis x right parenthesis$ is

The domain of the function $f left parenthesis x right parenthesis equals log subscript 2 invisible function application open parentheses log subscript 3 invisible function application open parentheses log subscript 4 invisible function application x close parentheses close parentheses$ is

The domain of the function $f left parenthesis x right parenthesis equals log subscript 2 invisible function application open parentheses log subscript 3 invisible function application open parentheses log subscript 4 invisible function application x close parentheses close parentheses$ is

The domain of the function $f left parenthesis x right parenthesis equals exp invisible function application open parentheses square root of 5 x minus 3 minus 2 x squared end root close parentheses$ is

The domain of the function $f left parenthesis x right parenthesis equals exp invisible function application open parentheses square root of 5 x minus 3 minus 2 x squared end root close parentheses$ is

The value of $tan invisible function application open curly brackets cos to the power of negative 1 end exponent invisible function application open parentheses negative 2 over 7 close parentheses minus pi over 2 close curly brackets$ is

The value of $tan invisible function application open curly brackets cos to the power of negative 1 end exponent invisible function application open parentheses negative 2 over 7 close parentheses minus pi over 2 close curly brackets$ is

$sin invisible function application open parentheses 1 half cos to the power of negative 1 end exponent invisible function application 4 over 5 close parentheses$ is equal to

$sin invisible function application open parentheses 1 half cos to the power of negative 1 end exponent invisible function application 4 over 5 close parentheses$ is equal to

$tan to the power of negative 1 end exponent invisible function application fraction numerator x over denominator square root of a squared minus x squared end root end fraction$ is equal to

$tan to the power of negative 1 end exponent invisible function application fraction numerator x over denominator square root of a squared minus x squared end root end fraction$ is equal to