Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

$tan to the power of negative 1 end exponent invisible function application fraction numerator x over denominator square root of a squared minus x squared end root end fraction$ is equal to

$2 \sin^{- 1} \frac{x}{a}$
$\sin^{- 1} \frac{2 x}{a}$
$\sin^{- 1} \frac{x}{a}$
$\cos^{- 1} \frac{x}{a}$

The correct answer is: $sin to the power of negative 1 end exponent invisible function application x over a$

Let $tan to the power of negative 1 end exponent invisible function application fraction numerator x over denominator square root of a squared minus x squared end root end fraction equals theta$
$not stretchy rightwards double arrow tan invisible function application theta equals fraction numerator x over denominator square root of a squared minus x squared end root end fraction$

$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell therefore sin invisible function application theta equals x over a end cell row cell not stretchy rightwards double arrow theta equals sin to the power of negative 1 end exponent invisible function application open parentheses x over a close parentheses end cell end table$

Related Questions to study

If $theta equals sin to the power of negative 1 end exponent invisible function application x plus cos to the power of negative 1 end exponent invisible function application x minus tan to the power of negative 1 end exponent invisible function application x comma 1 less or equal than x less than straight infinity$ , then the smallest interval in which θ lies is

If $theta equals sin to the power of negative 1 end exponent invisible function application x plus cos to the power of negative 1 end exponent invisible function application x minus tan to the power of negative 1 end exponent invisible function application x comma 1 less or equal than x less than straight infinity$ , then the smallest interval in which θ lies is

If $A equals open square brackets table attributes columnalign center center center center columnspacing 1em end attributes row cell cos squared end cell alpha cell cos invisible function application horizontal ellipsis horizontal ellipsis end cell cell alpha sin invisible function application horizontal ellipsis horizontal ellipsis end cell row cell cos invisible function application horizontal ellipsis end cell cell alpha sin end cell alpha cell sin squared invisible function application alpha end cell end table close square brackets$ and $A equals open square brackets table attributes columnalign center center center center columnspacing 1em end attributes row cell cos squared end cell beta cell cos invisible function application horizontal ellipsis sin end cell alpha row cos cell beta sin end cell cell sin squared invisible function application beta end cell beta end table close square brackets$ are two matrices such that the product AB is null matrix, then $alpha minus beta$ is

If $A equals open square brackets table attributes columnalign center center center center columnspacing 1em end attributes row cell cos squared end cell alpha cell cos invisible function application horizontal ellipsis horizontal ellipsis end cell cell alpha sin invisible function application horizontal ellipsis horizontal ellipsis end cell row cell cos invisible function application horizontal ellipsis end cell cell alpha sin end cell alpha cell sin squared invisible function application alpha end cell end table close square brackets$ and $A equals open square brackets table attributes columnalign center center center center columnspacing 1em end attributes row cell cos squared end cell beta cell cos invisible function application horizontal ellipsis sin end cell alpha row cos cell beta sin end cell cell sin squared invisible function application beta end cell beta end table close square brackets$ are two matrices such that the product AB is null matrix, then $alpha minus beta$ is

If $A equals left square bracket x y z right square bracket comma B equals open square brackets table attributes columnspacing 1em end attributes row cell a straight h invisible function application g end cell row cell h b f end cell row cell g f c end cell end table close square brackets$ and $C equals open square brackets table attributes columnalign left columnspacing 1em end attributes row x row y row z end table close square brackets$ Then, $B to the power of straight prime left parenthesis A B right parenthesis equals 0$ if

If $A equals left square bracket x y z right square bracket comma B equals open square brackets table attributes columnspacing 1em end attributes row cell a straight h invisible function application g end cell row cell h b f end cell row cell g f c end cell end table close square brackets$ and $C equals open square brackets table attributes columnalign left columnspacing 1em end attributes row x row y row z end table close square brackets$ Then, $B to the power of straight prime left parenthesis A B right parenthesis equals 0$ if

parallel

The function $f colon R not stretchy rightwards arrow R$ given by $f left parenthesis x right parenthesis equals x cubed minus 1$ is

The function $f colon R not stretchy rightwards arrow R$ given by $f left parenthesis x right parenthesis equals x cubed minus 1$ is

$f left parenthesis x right parenthesis equals x plus square root of x squared end root$ is a function from R to R, then $f left parenthesis x right parenthesis$ is

$f left parenthesis x right parenthesis equals x plus square root of x squared end root$ is a function from R to R, then $f left parenthesis x right parenthesis$ is

Which of the following functions is one-to -one?

Which of the following functions is one-to -one?

parallel

A mapping $f colon N not stretchy rightwards arrow N$ , where N is the set of natural numbers is defined as $f left parenthesis n right parenthesis equals open curly brackets table attributes columnspacing 1em end attributes row cell n squared comma text for end text n text odd end text end cell row cell 2 n plus 1 comma text for end text n text even end text end cell end table close$ For $n element of N$ Then, $f$ is

A mapping $f colon N not stretchy rightwards arrow N$ , where N is the set of natural numbers is defined as $f left parenthesis n right parenthesis equals open curly brackets table attributes columnspacing 1em end attributes row cell n squared comma text for end text n text odd end text end cell row cell 2 n plus 1 comma text for end text n text even end text end cell end table close$ For $n element of N$ Then, $f$ is

Let $A equals R minus left curly bracket 3 right curly bracket comma B equals R minus left curly bracket 1 right curly bracket text Let end text f colon A not stretchy rightwards arrow B$ be defined by $f left parenthesis x right parenthesis equals fraction numerator x minus 2 over denominator x minus 3 end fraction$ .Then,

Let $A equals R minus left curly bracket 3 right curly bracket comma B equals R minus left curly bracket 1 right curly bracket text Let end text f colon A not stretchy rightwards arrow B$ be defined by $f left parenthesis x right parenthesis equals fraction numerator x minus 2 over denominator x minus 3 end fraction$ .Then,

The mapping $f colon N not stretchy rightwards arrow N$ given $f left parenthesis n right parenthesis equals 1 plus n squared comma n element of N$ where N is the set of natural number, is

The mapping $f colon N not stretchy rightwards arrow N$ given $f left parenthesis n right parenthesis equals 1 plus n squared comma n element of N$ where N is the set of natural number, is

parallel

The function $f colon R not stretchy rightwards arrow R$ defined by $f left parenthesis x right parenthesis equals left parenthesis x minus 1 right parenthesis left parenthesis x minus 2 right parenthesis left parenthesis x minus 3 right parenthesis$ is

The function $f colon R not stretchy rightwards arrow R$ defined by $f left parenthesis x right parenthesis equals left parenthesis x minus 1 right parenthesis left parenthesis x minus 2 right parenthesis left parenthesis x minus 3 right parenthesis$ is

Let A be a set containing 10 distinct elements, then the total number of distinct function from A to A is

Let A be a set containing 10 distinct elements, then the total number of distinct function from A to A is

$A equals left curly bracket 1 comma 2 comma 3 comma 4 right curly bracket comma B left curly bracket 1 comma 2 comma 3 comma 4 comma 5 comma 6 right curly bracket$ are two sets, and function $f colon A not stretchy rightwards arrow B$ is defined by $f left parenthesis x right parenthesis equals x plus 2 straight for all x element of A$ , then the function $f$ is

$A equals left curly bracket 1 comma 2 comma 3 comma 4 right curly bracket comma B left curly bracket 1 comma 2 comma 3 comma 4 comma 5 comma 6 right curly bracket$ are two sets, and function $f colon A not stretchy rightwards arrow B$ is defined by $f left parenthesis x right parenthesis equals x plus 2 straight for all x element of A$ , then the function $f$ is

parallel

Let $n left parenthesis A right parenthesis equals 4 text and end text n left parenthesis B right parenthesis equals 6$ and The number of one to one functions from A to B is

Let $n left parenthesis A right parenthesis equals 4 text and end text n left parenthesis B right parenthesis equals 6$ and The number of one to one functions from A to B is

If denotes the set of all real numbers, then the function $f colon R not stretchy rightwards arrow R$ defined by $f left parenthesis x right parenthesis equals vertical line x vertical line$ is

If denotes the set of all real numbers, then the function $f colon R not stretchy rightwards arrow R$ defined by $f left parenthesis x right parenthesis equals vertical line x vertical line$ is

If $f colon R not stretchy rightwards arrow C$ is defined by $f left parenthesis x right parenthesis equals e to the power of 2 i x end exponent$ for $x element of R$ , then $f$ is (where C denotes the set of all complex numbers)

If $f colon R not stretchy rightwards arrow C$ is defined by $f left parenthesis x right parenthesis equals e to the power of 2 i x end exponent$ for $x element of R$ , then $f$ is (where C denotes the set of all complex numbers)

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.