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The sclerenchyma is composed of:

The sclerenchyma is composed of:

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General
Maths-

Tom has a large cone-shaped pinata hung from a tree. The height and radius of the pinata are 8 inches and 1 foot respectively. What is the volume of the pinata? Round your answer to two decimal places. (use π = 3.14)

Tom has a large cone-shaped pinata hung from a tree. The height and radius of the pinata are 8 inches and 1 foot respectively. What is the volume of the pinata? Round your answer to two decimal places. (use π = 3.14)

Maths-General
General
Maths-

The number of solutions of the pair of equations 2 sin squared space theta minus cos space 2 theta equals 0 comma 2 cos squared space theta minus 3 sin space theta equals 0 in the interval [0, 2straight pi] is

In this question, we have to find the number of solution. Now for that solve both the equation. We get sintheta  = ½ , so for the region is [ 0 , 2π] , ½ is positive so it only lies in first and second quadrant because sine is positive in first and second quadrant. The value of the  = π/6, 5π/6

The number of solutions of the pair of equations 2 sin squared space theta minus cos space 2 theta equals 0 comma 2 cos squared space theta minus 3 sin space theta equals 0 in the interval [0, 2straight pi] is

Maths-General

In this question, we have to find the number of solution. Now for that solve both the equation. We get sintheta  = ½ , so for the region is [ 0 , 2π] , ½ is positive so it only lies in first and second quadrant because sine is positive in first and second quadrant. The value of the  = π/6, 5π/6

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If an event has a probability of success p and a probability of failure q , then each term in the expansion of (p +q)n represents a probability. For example , if a basketball player makes 60% of his free throw attempts , p= 0.6 and q= 0.4. To find the probability the basketball player will make exactly h out of k free throws, find C subscript k minus h end subscript p to the power of h q to the power of k minus h end exponent text  where  end text C subscript k minus h end subscript a coefficient of row k of Pascal’s triangle is, p is the probability of success, and q is the probability of failure.

Probability is the ratio of the number of outcomes in an exhaustive set of equally likely outcomes that produce a given event to the total number of possible outcomes

If an event has a probability of success p and a probability of failure q , then each term in the expansion of (p +q)n represents a probability. For example , if a basketball player makes 60% of his free throw attempts , p= 0.6 and q= 0.4. To find the probability the basketball player will make exactly h out of k free throws, find C subscript k minus h end subscript p to the power of h q to the power of k minus h end exponent text  where  end text C subscript k minus h end subscript a coefficient of row k of Pascal’s triangle is, p is the probability of success, and q is the probability of failure.

Maths-General

Probability is the ratio of the number of outcomes in an exhaustive set of equally likely outcomes that produce a given event to the total number of possible outcomes

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Maths-

How many terms are there in the expansion of left parenthesis 2 x plus 7 y right parenthesis to the power of 9

The expansion of (x + y)n can be found using the (n+1)th row of the Pascal’s triangle.

How many terms are there in the expansion of left parenthesis 2 x plus 7 y right parenthesis to the power of 9

Maths-General

The expansion of (x + y)n can be found using the (n+1)th row of the Pascal’s triangle.

General
Maths-

A Pythagorean triple is a set of three positive integers a, b and c that satisfy a squared plus b squared equals c squared .The Identity open parentheses x squared minus y squared close parentheses squared plus left parenthesis 2 x y right parenthesis squared equals open parentheses x squared plus y squared close parentheses squared can be used to generate Pythagorean triples. Use the identity to generate a Pythagorean triple when x=5 and y= 4

Pythagorean property is an important property in right angled triangles. It helps you to find the measurements of the corresponding triangle.

A Pythagorean triple is a set of three positive integers a, b and c that satisfy a squared plus b squared equals c squared .The Identity open parentheses x squared minus y squared close parentheses squared plus left parenthesis 2 x y right parenthesis squared equals open parentheses x squared plus y squared close parentheses squared can be used to generate Pythagorean triples. Use the identity to generate a Pythagorean triple when x=5 and y= 4

Maths-General

Pythagorean property is an important property in right angled triangles. It helps you to find the measurements of the corresponding triangle.

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Maths-

The dimensions of a rectangle are shown. Write the area of the rectangle as a sum of cubes .

The area of a rectangle with length l and width w is A = lw

The dimensions of a rectangle are shown. Write the area of the rectangle as a sum of cubes .

Maths-General

The area of a rectangle with length l and width w is A = lw

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Maths-

A Medium sized Shipping box with side length s units has a volume of S3  cubic units.
a. A Large shipping box has side lengths that are 3 units longer than the medium shipping box. Write a binomial expression for the volume of the large shipping box .
b. Expand the polynomial in part A to simplify the volume of the large shipping box ?

The volume of a cuboid with side length a is, V = a3.

A Medium sized Shipping box with side length s units has a volume of S3  cubic units.
a. A Large shipping box has side lengths that are 3 units longer than the medium shipping box. Write a binomial expression for the volume of the large shipping box .
b. Expand the polynomial in part A to simplify the volume of the large shipping box ?

Maths-General

The volume of a cuboid with side length a is, V = a3.

General
Maths-

Use the binomial theorem to expand the expressions: open parentheses m squared plus n over 2 close parentheses cubed

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

Use the binomial theorem to expand the expressions: open parentheses m squared plus n over 2 close parentheses cubed

Maths-General

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

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Maths-

Use the binomial theorem to expand the expressions: left parenthesis 4 g plus 2 h right parenthesis to the power of 4

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

Use the binomial theorem to expand the expressions: left parenthesis 4 g plus 2 h right parenthesis to the power of 4

Maths-General

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

General
Maths-

Use the binomial theorem to expand the expressions: left parenthesis 3 x minus 0.2 right parenthesis cubed

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

Use the binomial theorem to expand the expressions: left parenthesis 3 x minus 0.2 right parenthesis cubed

Maths-General

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

General
Maths-

Use the binomial theorem to expand the expressions: left parenthesis n plus 5 right parenthesis to the power of 5

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

Use the binomial theorem to expand the expressions: left parenthesis n plus 5 right parenthesis to the power of 5

Maths-General

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

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General
Maths-

Use the binomial theorem to expand the expressions: left parenthesis 2 m plus 2 n right parenthesis to the power of 6

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

Use the binomial theorem to expand the expressions: left parenthesis 2 m plus 2 n right parenthesis to the power of 6

Maths-General

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

General
Maths-

Use the binomial theorem to expand the expressions: left parenthesis d minus 3 right parenthesis to the power of 4

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

Use the binomial theorem to expand the expressions: left parenthesis d minus 3 right parenthesis to the power of 4

Maths-General

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

General
Maths-

Use the binomial theorem to expand the expressions: open parentheses x cubed plus y squared close parentheses to the power of 6

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

Use the binomial theorem to expand the expressions: open parentheses x cubed plus y squared close parentheses to the power of 6

Maths-General

The answer can also be found using the Pascal’s triangle. For the expansion of the expression (x + y)n , we would consider the (n+1)th row in the triangle.

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