science
Grade-11
Easy

Question

Let us consider two cars, A and B, are moving with constant acceleration 4 m/s2 and constant velocity 6 m/s with t = 0 s, both cars are 20 m apart, car A is behind car B, find the time when car A overtakes car B.

  1. 5.2
  2. 3.1
  3. 3.4
  4. 6.2

hintHint:

  • Use equations of motion.

The correct answer is: 3.4


    • Given that Car A is moving with acceleration 4 m/s^2 with no initial velocity .
    • Car B is moving with constant 6 m/s. 
    • The Distance covered by each car is equal during the instant of Overtaking.
    • By the equation of motion ut+1/2at^2 = ut + 20
                                                1/2(4)t2 = 6t + 20 
    • Solving the quadratic equation we get t = 3.4 (approx)

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