Maths-
General
Easy

Question

Show the conjecture is false by finding a counterexample. The square root of any positive integer x is always less than x.

hintHint:

Take an example and check.

The correct answer is: Thus we get 1 as the integer, whose square root is equal to itself to disprove the conjecture.


    Complete step by step solution:
    Here take the integer x = 1
    On taking square root, we get square root of x equals square root of 1 equals 1
    Here,  is never less than1.
    Thus we get 1 as the integer, whose square root is equal to itself to disprove the
    conjecture.

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