Maths-
General
Easy
Question
Solve the following equation : 2(1 - x) + 5x = 3(x + 1) and say whether it is having one solution , no solution or infinitely many solutions ?
Hint:
An equation where no value can be substituted for the variable which will satisfy the equation i.e. for no value of x (or any other variable in the equation), would LHS equal RHS.
Hence, an equation where LHS ≠ RHS for any value of x has no solutions.
We will simplify the given equation and check whether LHS = RHS or not.
The correct answer is: The given equation 2(1 - x) + 5x = 3(x + 1) can be classified as having no solution
Step-by-step solution:-
Simplifying the given equation i.e. 2(1 - x) + 5x = 3(x + 1), we get-
2(1 - x) + 5x = 3(x + 1)
∴ 2 - 2x + 5x = 3x + 3
∴ -2x + 5x - 3x = 3 - 2
∴ 0 ≠ 1
∴ LHS ≠ RHS
Since in the above equation, LHS is not equal to RHS, the given equation has no solutions.
Final Answer:-
∴ The given equation 2(1 - x) + 5x = 3(x + 1) can be classified as having no solution.
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