Maths-
General
Easy

Question

square root of 2 x plus 6 end root plus 4 equals x plus 3
What is the solution set of the equation above?

  1. {-1}
  2. {5}
  3. {-1,5}
  4. {0, -1, 5}

hintHint:

e perform algebraic manipulations to solve the problem.
 

The correct answer is: {-1,5}


    not stretchy rightwards double arrow left parenthesis x minus 5 right parenthesis left parenthesis x plus 1 right parenthesis equals 0
    Step 1 of 2:
    Given, square root of 2 x plus 6 end root plus 4 equals x plus 3
    not stretchy rightwards double arrow square root of 2 x plus 6 end root equals x plus 3 minus 4
    not stretchy rightwards double arrow square root of 2 x plus 6 end root equals x minus 1
    Taking squares on both sides, we get
    not stretchy rightwards double arrow left parenthesis square root of 2 x plus 6 end root right parenthesis squared equals left parenthesis x minus 1 right parenthesis squared
    not stretchy rightwards double arrow 2 x plus 6 equals x squared minus 2 x plus 1
    not stretchy rightwards double arrow x squared minus 2 x plus 1 minus 2 x minus 6 equals 0
    not stretchy rightwards double arrow x squared minus 4 x minus 5 equals 0
    not stretchy rightwards double arrow x squared minus left parenthesis 5 minus 1 right parenthesis x minus 5 equals 0
    not stretchy rightwards double arrow x squared minus 5 x plus x minus 5 equals 0
    not stretchy rightwards double arrow x left parenthesis x minus 5 right parenthesis plus left parenthesis x minus 5 right parenthesis equals 0
    Step 2 of 2:
    If product of two numbers is zero, then either of them must be zero.
    Hence, either x - 5 = 0 or, x + 1=0
    ∴x = 5, - 1
    Final Answer:
    The solution set of the equation is— C) {-1.5}.

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