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Maths-

General

Easy

Question

The equation of the line passing through (3, –4) and perpendicular to the line joining (–2, 6) and (5, 9) is

7x + 3y – 9 = 0
7x + 3y + 9 = 0
7x – 3y – 9 = 0
7x – 3y + 9 = 0

The correct answer is: 7x + 3y – 9 = 0

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As shown in the diagram, points $p subscript 1 end subscript comma p subscript 2 end subscript comma p subscript 3 end subscript horizontal ellipsis horizontal ellipsis horizontal ellipsis. p subscript 10 end subscript$ are either the Then the number of groups of four points

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Which of the following belongs to, e.g. (double grade) orbitals?

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You add:
Which picture shows the sum:

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4th

5th

6th

7th

8th

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71.33

84.01

These are the first eight ionization energies for a particular neutral atom. All values are expressed in MJ mol^-1. How many valence electrons do/does this atom possess?

1st

2nd

3rd

4th

5th

6th

7th

8th

1.31

3.39

5.30

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10.99

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71.33

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