Maths-
General
Easy

Question

The expression fraction numerator x squared plus 2 x plus 1 over denominator x squared plus 2 x plus 7 end fraction lies in the interval ; (x ε R) –

  1. [0, –1]
  2. left parenthesis negative straight infinity comma 0 right square bracket union left square bracket 1 comma straight infinity right parenthesis
  3. [0, 1)
  4. None of these

hintHint:

In the question, we are required to find the range of the given expression, fraction numerator x squared plus 2 x plus 1 over denominator x squared plus 2 x plus 7 end fraction given that the domain is R.

The correct answer is: [0, 1)


    Step by step solution:
    Given expression, fraction numerator x squared plus 2 x plus 1 over denominator x squared plus 2 x plus 7 end fraction
    Let y = fraction numerator x squared plus 2 x plus 1 over denominator x squared plus 2 x plus 7 end fraction
    rightwards double arrow y left parenthesis x squared plus 2 x plus 7 right parenthesisequals space x squared plus 2 x plus 1
    rightwards double arrow x squared y space plus space 2 x y space plus space 7 yequals space x squared plus 2 x plus 1
    rightwards double arrow x squared left parenthesis y minus 1 right parenthesisplus space 2 x left parenthesis y minus 1 right parenthesisplus left parenthesis 7 y minus 1 right parenthesisequals 0
    Since, x element of R
    Therefore, b squared minus 4 a c greater or equal than 0
    rightwards double arrow left curly bracket 2 left parenthesis y minus 1 right parenthesis right curly bracket squarednegative 4 left parenthesis y minus 1 right parenthesis left parenthesis 7 y minus 1 right parenthesisgreater or equal than 0
    rightwards double arrow 4 left parenthesis y squared minus 2 y plus 1 right parenthesisnegative 4 left parenthesis 7 y squared minus 8 y plus 1 right parenthesisgreater or equal than 0
    rightwards double arrow y squared minus 2 y plus 1negative 7 y squared plus 8 y minus 1greater or equal than 0
    rightwards double arrow negative 6 y squared plus 6 y greater or equal than 0
    rightwards double arrow 6 y squared minus 6 y less or equal than 0
    rightwards double arrow 6 y left parenthesis y minus 1 right parenthesis less or equal than 0
    rightwards double arrow y space element of space left square bracket 0 comma 1 right square bracket
    Thus, the expression lies in the interval [0,1]
    Hence, option(c) is the correct option.

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