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Question

The front row of an auditorium has 10 seats. There are 50 rows in total. If each row has 2 more seats than the row before it, which expression gives the total number of seats in the last row?

  1. 10 plus 2 left parenthesis 50 minus 1 right parenthesis
  2. 10 plus 2 left parenthesis 50 right parenthesis
  3. 50 left parenthesis 10 plus 2 right parenthesis
  4. 10 plus 2 to the power of 50

hintHint:

Hint:
If we carefully observe the seating, it is seen that the seats in the auditorium are arranged in an Arithmetic Progression. An arithmetic progression is such a sequence of numbers where the difference between consecutive terms is constant. Here, each row has 2 more seats than the row before it, so the difference between two consecutive rows is constant. We need to find the number of seats in the last row which is equivalent to finding the last term of this A.P. series

The correct answer is: 10 plus 2 left parenthesis 50 minus 1 right parenthesis


    Given,
    In an auditorium, number of seats in front row = 10
    Total number of rows = 50
    Difference in the number of seats in consecutive rows = 2
    We consider the Arithmetic Progression (A. P.) as follows:
    First term of the A. P. (a) = 10
    Total number of the terms (n) = 50
    Common difference (d) = 2
    The total number of seats in the last row is given by the last term of this series.
    The last term of series is given by
    a subscript n equals a plus left parenthesis n minus 1 right parenthesis d
    Putting the values of  in the above formula, we get
    a subscript n equals 10 plus left parenthesis 50 minus 1 right parenthesis 2
    Rewriting the above equation, we have
    a subscript n equals 10 plus 2 left parenthesis 50 minus 1 right parenthesis
    Thus, the correct option is A)

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