Question
The front row of an auditorium has 10 seats. There are 50 rows in total. If each row has 2 more seats than the row before it, which expression gives the total number of seats in the last row?
Hint:
Hint:
If we carefully observe the seating, it is seen that the seats in the auditorium are arranged in an Arithmetic Progression. An arithmetic progression is such a sequence of numbers where the difference between consecutive terms is constant. Here, each row has 2 more seats than the row before it, so the difference between two consecutive rows is constant. We need to find the number of seats in the last row which is equivalent to finding the last term of this A.P. series
The correct answer is:
Given,
In an auditorium, number of seats in front row = 10
Total number of rows = 50
Difference in the number of seats in consecutive rows = 2
We consider the Arithmetic Progression (A. P.) as follows:
First term of the A. P. (a) = 10
Total number of the terms (n) = 50
Common difference (d) = 2
The total number of seats in the last row is given by the last term of this series.
The last term of series is given by
Putting the values of in the above formula, we get
Rewriting the above equation, we have
Thus, the correct option is A)
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