Maths-
General
Easy

Question


The line graph above shows the average price of one metric ton of oranges, in dollars, for each of seven months in 2014.
Between which two consecutive months shown did the average price of one metric ton of oranges decrease the most?

  1. March to April
  2. May to June
  3. June to July
  4. July to August

hintHint:

Hint:
The graph gives the average price on one metric ton of oranges for
seven months. To find the decrease in average price of two
consecutive months, we simply subtract the average price in the
second month from the average price in the first month. As we are
not given exact values, we approximate the average price from the graph.

The correct answer is: June to July


    From the graph it is clear that the average price of the oranges
    increased till April and then it started decreasing. So, we calculate
    the decrease in the average price of one metric ton of oranges for the next consecutive  months.
    We are given,
    Approximate average price of one metric ton of oranges in April = 841$
    Approximate average price of one metric ton of oranges in May = 835$
    Approximate average price of one metric ton of oranges in June= 833$
    Approximate average price of one metric ton of oranges in July= 780$
    Approximate average price of one metric ton of oranges in August=770
    For their, calculating the decrease in every consecutive months:
    Decrease in average price between April and May= 841-835 = 6$
    Decrease in average price between May and June= 835-833= 3$
    Decrease in average price between June and July= 833-780= 53$
    Decrease in average price between July and August = 780-770=10$
    Thus, the decrease in average price of one metric ton of oranges is maximum in the consecutive months of June and July.
    The correct option is C)

    Note:
    A simpler way of solving this question is to check where the decrease in the graph has the steepest slope between two months. It is clearly between the months June and July. Here, it is obvious; but that may not be the case in other problems. So, we need to always calculate the actual decrease in the value.

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