Maths-
General
Easy

Question


The table above shows two lists of numbers. Which of the following is a true statement comparing list A  and list B?

  1. The means are the same, and the standard deviations are different.
  2. The means are the same, and the standard deviations are the same.
  3. The means are different, and the standard deviations are different.
  4. The means are different, and the standard deviations are the same.

hintHint:

Hint:
  • Mean of any n data is ratio of sum of all n data to number of data
  • Standard deviation of n data is square root of fraction numerator vertical line x minus mean invisible function application vertical line squared over denominator n end fraction end root

The correct answer is: The means are the same, and the standard deviations are different.


    Explanation:
    • We have given two set of data in table form.
    • We have to find their means and standard deviation and compare them
    Step 1 of 1:
    The given data in table form is

    Now, For List A,
    First calculate mean
    So,
    Mean =fraction numerator 1 plus 2 plus 3 plus 4 plus 5 plus 6 over denominator 6 end fraction
    equals 21 over 6
    = 3.5
    And standard deviation will besquare root of fraction numerator vertical line x minus mean invisible function application vertical line squared over denominator n end fraction end root
    So,
    equals square root of fraction numerator vertical line 1 minus 3.5 vertical line squared plus vertical line 2 minus 3.5 vertical line squared plus vertical line 3 minus 3.5 vertical line squared plus vertical line 4 minus 3.5 vertical line squared plus vertical line 5 minus 3.5 vertical line squared plus vertical line 6 minus 3.5 vertical line squared over denominator 6 end fraction end root
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell equals square root of 2.917 end root end cell row cell equals 1.71 end cell end table
    Now, For List B
    text  Mean  end text equals fraction numerator 2 plus 3 plus 3 plus 4 plus 4 plus 5 over denominator 6 end fraction
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell equals 21 over 6 end cell row cell equals 3.5 end cell end table
    And standard deviation will be
    equals square root of fraction numerator vertical line 2 minus 3.5 vertical line squared plus vertical line 3 minus 3.5 vertical line squared plus vertical line 3 minus 3.5 vertical line squared plus vertical line 4 minus 3.5 vertical line squared plus vertical line 4 minus 3.5 vertical line squared plus vertical line 5 minus 3.5 vertical line squared over denominator 6 end fraction end root
    equals square root of 0.917 end root
    = 0.96
    Thus, List A and List B have the same mean but different standard deviation.
    Hence, Option A is correct.

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