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Maths-

General

Easy

Question

The value of $fraction numerator 3 plus cot 76 to the power of ring operator cot 16 to the power of ring operator over denominator cot 76 to the power of ring operator plus cot 16 to the power of ring operator end fraction$ is

tan44°
$\cot 46^{\circ}$
$\tan 2^{\circ}$
$\tan 46^{\circ}$

The correct answer is: $tan invisible function application 46 to the power of ring operator$

$fraction numerator 3 plus cot 76 to the power of ring operator cot 16 to the power of ring operator over denominator cot 76 to the power of ring operator plus cot 16 to the power of ring operator end fraction equals fraction numerator 3 plus begin display style fraction numerator cos 76 to the power of ring operator cos 16 to the power of ring operator over denominator sin 76 degree sin 16 degree end fraction end style over denominator begin display style fraction numerator cos 76 to the power of ring operator over denominator sin 76 degree end fraction end style plus begin display style fraction numerator cos 16 to the power of ring operator over denominator sin 16 degree end fraction end style end fraction equals fraction numerator fraction numerator 3 sin 76 degree sin 16 degree plus cos 76 to the power of ring operator cos 16 to the power of ring operator over denominator sin 76 degree sin 16 degree end fraction over denominator begin display style fraction numerator cos 76 to the power of ring operator sin 16 degree plus cos 16 to the power of ring operator sin 76 degree over denominator sin 76 degree sin 16 degree end fraction end style end fraction equals fraction numerator 3 sin 76 degree sin 16 degree plus cos 76 to the power of ring operator cos 16 to the power of ring operator over denominator begin display style cos 76 to the power of ring operator sin 16 degree plus cos 16 to the power of ring operator sin 76 degree end style end fraction equals fraction numerator 2 sin 76 degree sin 16 degree plus open parentheses sin 76 degree sin 16 degree plus cos 76 to the power of ring operator cos 16 to the power of ring operator close parentheses over denominator begin display style cos 76 to the power of ring operator sin 16 degree plus cos 16 to the power of ring operator sin 76 degree end style end fraction open parentheses because sin A sin B plus cos A cos B equals C o s open parentheses A minus B close parentheses space a n d space cos A sin B plus cos A sin B equals sin open parentheses A plus B close parentheses close parentheses equals fraction numerator 2 sin 76 degree sin 16 degree plus open parentheses cos open parentheses 76 degree minus 16 degree close parentheses close parentheses over denominator begin display style sin open parentheses 76 degree plus 16 degree close parentheses end style end fraction equals fraction numerator 2 sin 76 degree sin 16 degree plus open parentheses cos open parentheses 60 degree close parentheses close parentheses over denominator begin display style sin open parentheses 92 degree close parentheses end style end fraction open parentheses because 2 sin A sin B equals cos open parentheses A minus B close parentheses minus cos open parentheses A plus B close parentheses close parentheses equals fraction numerator cos open parentheses 76 degree minus 16 degree close parentheses minus cos open parentheses 76 degree plus 16 degree close parentheses plus open parentheses cos open parentheses 60 degree close parentheses close parentheses over denominator begin display style sin open parentheses 92 degree close parentheses end style end fraction equals fraction numerator cos open parentheses 60 degree close parentheses minus cos open parentheses 92 degree close parentheses plus open parentheses cos open parentheses 60 degree close parentheses close parentheses over denominator begin display style sin open parentheses 92 degree close parentheses end style end fraction equals fraction numerator 1 minus cos open parentheses 92 degree close parentheses over denominator begin display style sin open parentheses 92 degree close parentheses end style end fraction open parentheses because 1 minus cos 2 A equals 2 sin squared A space a n d space sin 2 A equals 2 sin A cos A close parentheses equals fraction numerator 2 sin squared 46 degree over denominator 2 sin 46 degree cos 46 degree end fraction equals fraction numerator sin 46 degree over denominator cos 46 degree end fraction equals tan 46 degree$

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If are four angles then $sin invisible function application left parenthesis A minus B right parenthesis times cos invisible function application left parenthesis A plus B right parenthesis plus sin invisible function application left parenthesis B minus C right parenthesis cos invisible function application left parenthesis B plus C right parenthesis plus sin invisible function application left parenthesis C minus D right parenthesis$ . $cos invisible function application left parenthesis C plus D right parenthesis plus sin invisible function application left parenthesis D minus A right parenthesis times cos invisible function application left parenthesis D plus A right parenthesis equals$

If are four angles then $sin invisible function application left parenthesis A minus B right parenthesis times cos invisible function application left parenthesis A plus B right parenthesis plus sin invisible function application left parenthesis B minus C right parenthesis cos invisible function application left parenthesis B plus C right parenthesis plus sin invisible function application left parenthesis C minus D right parenthesis$ . $cos invisible function application left parenthesis C plus D right parenthesis plus sin invisible function application left parenthesis D minus A right parenthesis times cos invisible function application left parenthesis D plus A right parenthesis equals$

If $tan space theta subscript 1 comma tan space theta subscript 2 comma tan space theta subscript 3$ and $tan space theta subscript 4$ are the roots of the equation $x to the power of 4 minus x cubed sin space 2 beta plus x squared cos space 2 beta minus x cos space beta minus sin space beta equals 0$ then $tan space open parentheses theta subscript 1 plus theta subscript 2 plus theta subscript 3 plus theta subscript 4 close parentheses$ is equal to

If $tan space theta subscript 1 comma tan space theta subscript 2 comma tan space theta subscript 3$ and $tan space theta subscript 4$ are the roots of the equation $x to the power of 4 minus x cubed sin space 2 beta plus x squared cos space 2 beta minus x cos space beta minus sin space beta equals 0$ then $tan space open parentheses theta subscript 1 plus theta subscript 2 plus theta subscript 3 plus theta subscript 4 close parentheses$ is equal to

Formula of the following silicate anion is

Formula of the following silicate anion is

chemistry-General

parallel

Sulphide mineral + $CN to the power of minus rightwards arrow with straight O subscript 2 on top open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus 2 open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus plus Zn not stretchy rightwards arrow open square brackets Zn left parenthesis CN right parenthesis subscript 4 close square brackets to the power of 2 minus end exponent plus 2 M$ M
can be

Sulphide mineral + $CN to the power of minus rightwards arrow with straight O subscript 2 on top open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus 2 open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus plus Zn not stretchy rightwards arrow open square brackets Zn left parenthesis CN right parenthesis subscript 4 close square brackets to the power of 2 minus end exponent plus 2 M$ M
can be

chemistry-General

The adjoining figure gives the road plan of lanes connecting two parallel roads AB and FJ Aman walking on the road AB takes a turn at random to reach the road FJ It is known that he reaches the road FJ from $O$ by taking a straight line The chance that he moves on a straight line from the road AB to the road FJ is.

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parallel

If $sin space pi over 18 sin space fraction numerator 5 pi over denominator 18 end fraction sin space fraction numerator 7 pi over denominator 18 end fraction$ =

If $sin space pi over 18 sin space fraction numerator 5 pi over denominator 18 end fraction sin space fraction numerator 7 pi over denominator 18 end fraction$ =

The value of $sin invisible function application 47 to the power of ring operator plus sin invisible function application 61 to the power of ring operator minus sin invisible function application 11 to the power of ring operator minus sin invisible function application 25 to the power of ring operator$ is

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If ABC is a triangle and $tan space A over 2 comma tan space B over 2 comma tan space C over 2$ are H.P then the minimum value of $cot space B over 2$ is equal to

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parallel

If $theta equals pi over 2 to the power of n plus 1 end exponent$ then $cos space theta cos space 2 theta cos space 2 squared theta horizontal ellipsis cos space 2 to the power of n minus 1 end exponent theta$ is equal to

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If A,B,C re in A.P and $B equals pi over 4$ then $tan space A tan space B tan C$ =

If A,B,C re in A.P and $B equals pi over 4$ then $tan space A tan space B tan C$ =

If $alpha comma beta comma gamma$ do not differ by a multiple of $straight pi$ and if $fraction numerator cos space left parenthesis alpha plus theta right parenthesis over denominator sin space left parenthesis beta plus gamma right parenthesis end fraction equals fraction numerator cos begin display style space end style left parenthesis beta plus theta right parenthesis over denominator sin begin display style space end style left parenthesis gamma plus alpha right parenthesis end fraction equals fraction numerator cos begin display style space end style left parenthesis gamma plus theta right parenthesis over denominator sin begin display style space end style left parenthesis alpha plus beta right parenthesis end fraction equals k$ Then k equals

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parallel

From the figure AOC=

From the figure AOC=

In $capital delta$ ABC, D,E,F are the midpoints of sides BC, CA and AB respectively then ar $open parentheses B D E F close parentheses equals$

In $capital delta$ ABC, D,E,F are the midpoints of sides BC, CA and AB respectively then ar $open parentheses B D E F close parentheses equals$

When the solute has been added in the solution, then following observation can be made ?

When the solute has been added in the solution, then following observation can be made ?

parallel

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