Maths-
General
Easy
Question
Three sides of a triangle are (2x-y+4z) , (4x-3y +2z ) and (6x-5z+2y ) . Find its
perimeter?
Hint:
The concept used in this question is the perimeter of a triangle.
○ Perimeter of triangle is given by
Sum of sides of triangle.
○ If sides of triangle are a, b, and c then perimeter will be given by
a + b + c
The correct answer is: Hence, the perimeter of the triangle is 12x - 2y + z.
- Step by step explanation:
○ Given:
Three sides of a triangle are
(2x-y+4z), (4x-3y +2z ) and (6x-5z+2y )
○ Step 1:
○ Let,
side a of triangle be (2x-y+4z).
side a of triangle be (4x-3y +2z).
side a of triangle be (6x-5z+2y).
○ Step 2:
○ The perimeter of the triangle is a + b + c.
a + b + c = (2x-y+4z) + (4x-3y +2z) + (6x-5z + 2y)
○ Step 3:
○ Group the like terms.
a + b + c = (2x + 4x + 6x) - (y + 3y - 2y) + (4z + 2z - 5z )
a + b + c = (12x) - (2y) + (z)
- Final Answer:
Hence, the perimeter of the triangle is 12x - 2y + z.
○ Step 1:
○ Let,
side a of triangle be (2x-y+4z).
side a of triangle be (4x-3y +2z).
side a of triangle be (6x-5z+2y).
○ Step 2:
○ The perimeter of the triangle is a + b + c.
a + b + c = (2x-y+4z) + (4x-3y +2z) + (6x-5z + 2y)○ Step 3:
○ Group the like terms.
a + b + c = (2x + 4x + 6x) - (y + 3y - 2y) + (4z + 2z - 5z )a + b + c = (12x) - (2y) + (z)Related Questions to study
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