Maths-
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Question

To verify Lagrange’s mean value theorem, there exists at least one point celement of(a,b) such that

  1. f to the power of straight prime left parenthesis c right parenthesis equals fraction numerator f left parenthesis a right parenthesis minus f left parenthesis b right parenthesis over denominator b minus a end fraction
  2. f to the power of straight prime left parenthesis c right parenthesis equals fraction numerator f left parenthesis b right parenthesis minus f left parenthesis a right parenthesis over denominator b minus a end fraction
  3. straight f to the power of straight prime left parenthesis straight c right parenthesis equals fraction numerator straight f left parenthesis straight a right parenthesis minus straight f left parenthesis straight b right parenthesis over denominator straight b minus straight a end fraction
  4. None

The correct answer is: f to the power of straight prime left parenthesis c right parenthesis equals fraction numerator f left parenthesis b right parenthesis minus f left parenthesis a right parenthesis over denominator b minus a end fraction


    If a function y equals f left parenthesis x right parenthesis is continuous from the interval left square bracket a comma b right square bracket and is differentiable in the open interval left parenthesis a comma b right parenthesis, then according to Lagrange Mean Value Theorem (LMVT) there exists a point C in the interval left parenthesis a comma b right parenthesis such that
    f apostrophe left parenthesis c right parenthesis equals fraction numerator f left parenthesis b right parenthesis minus f left parenthesis a right parenthesis over denominator b minus a end fraction

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