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Two point masses A and B having masses in the ratio 4:3 are seprated by a distance of 1m. When another point mass c of mass M is placed in between A and B the forces A and C is 1/3rd of the force between b and C, Then the distance C form is...m
- 23
- 1/3
- 1/4
- 2/7
The correct answer is: 23
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