Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis left parenthesis 1 plus x right parenthesis left parenthesis 1 divided by 5 right parenthesis minus left parenthesis 1 minus x right parenthesis left parenthesis 1 divided by 2 right parenthesis right parenthesis divided by x$

$1 / 4$
4
1
0

The correct answer is: 0

Related Questions to study

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis s i n left parenthesis pi c o s squared x right parenthesis right parenthesis divided by x squared$

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis s i n left parenthesis pi c o s squared x right parenthesis right parenthesis divided by x squared$

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis e to the power of x minus e cubed right parenthesis divided by left parenthesis x rightwards arrow 0 right parenthesis$

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis e to the power of x minus e cubed right parenthesis divided by left parenthesis x rightwards arrow 0 right parenthesis$

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis e cubed x minus e cubed right parenthesis divided by x$

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis e cubed x minus e cubed right parenthesis divided by x$

parallel

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis e to the power of 7 x minus 1 right parenthesis divided by 7 x$

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis e to the power of 7 x minus 1 right parenthesis divided by 7 x$

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis s i n a x right parenthesis divided by left parenthesis x c o s x right parenthesis$

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis s i n a x right parenthesis divided by left parenthesis x c o s x right parenthesis$

$L t left parenthesis x rightwards arrow 3 right parenthesis left parenthesis x minus 3 right parenthesis divided by √ left parenthesis vertical line x squared minus 9 vertical line right parenthesis$

$L t left parenthesis x rightwards arrow 3 right parenthesis left parenthesis x minus 3 right parenthesis divided by √ left parenthesis vertical line x squared minus 9 vertical line right parenthesis$

parallel

$L t left parenthesis x rightwards arrow 0 right parenthesis x squared c o s 2 divided by x$

$L t left parenthesis x rightwards arrow 0 right parenthesis x squared c o s 2 divided by x$

$L t left parenthesis x rightwards arrow d right parenthesis left parenthesis left parenthesis 2 vertical line x vertical line right parenthesis divided by x plus x plus 1 right parenthesis$

For such questions, we should know different formulas of limit.

$L t left parenthesis x rightwards arrow d right parenthesis left parenthesis left parenthesis 2 vertical line x vertical line right parenthesis divided by x plus x plus 1 right parenthesis$

For such questions, we should know different formulas of limit.

$L subscript left parenthesis t rightwards arrow 2 right parenthesis left parenthesis vertical line x minus 2 vertical line right parenthesis divided by left parenthesis x minus 2 right parenthesis$

$L subscript left parenthesis t rightwards arrow 2 right parenthesis left parenthesis vertical line x minus 2 vertical line right parenthesis divided by left parenthesis x minus 2 right parenthesis$

parallel

$L subscript left parenthesis x rightwards arrow 0 right parenthesis left parenthesis 1 minus c o s invisible function application m x right parenthesis divided by left parenthesis 1 minus c o s invisible function application n x right parenthesis comma n not equal to 0$

$L subscript left parenthesis x rightwards arrow 0 right parenthesis left parenthesis 1 minus c o s invisible function application m x right parenthesis divided by left parenthesis 1 minus c o s invisible function application n x right parenthesis comma n not equal to 0$

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis 1 minus c o s 2 m x right parenthesis divided by left parenthesis s i n squared n x right parenthesis left parenthesis m comma n element of Z right parenthesis$

$L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis 1 minus c o s 2 m x right parenthesis divided by left parenthesis s i n squared n x right parenthesis left parenthesis m comma n element of Z right parenthesis$

$L t subscript left parenthesis x rightwards arrow 0 right parenthesis left parenthesis x t a n invisible function application 2 x minus 2 x t a n invisible function application x right parenthesis divided by left parenthesis left parenthesis 1 minus c o s invisible function application 2 x right parenthesis squared right parenthesis$

$L t subscript left parenthesis x rightwards arrow 0 right parenthesis left parenthesis x t a n invisible function application 2 x minus 2 x t a n invisible function application x right parenthesis divided by left parenthesis left parenthesis 1 minus c o s invisible function application 2 x right parenthesis squared right parenthesis$

parallel

The Lewis symbols of three unknown elements are as follows :
i)
ii)
iii)
Write the formula of the different compounds formed by their combination.

The Lewis symbols of three unknown elements are as follows :
i)
ii)
iii)
Write the formula of the different compounds formed by their combination.

Chemistry-General

How many $sigma$ and $pi$ -bonds are there in the molecule of tetracyanoethylene ?

How many $sigma$ and $pi$ -bonds are there in the molecule of tetracyanoethylene ?

Chemistry-General

If $stack a with ‾ on top comma stack b with ‾ on top$ are non -zero, non -parallel vectors then the value of $vertical line stack a with ‾ on top plus stack b with ‾ on top plus stack a with ‾ on top cross times stack b with rightwards arrow on top vertical line to the power of 2 end exponent plus vertical line stack a with rightwards arrow on top plus stack b with ‾ on top minus stack a with ‾ on top cross times stack b with ‾ on top vertical line to the power of 2 end exponent$ equals

If $stack a with ‾ on top comma stack b with ‾ on top$ are non -zero, non -parallel vectors then the value of $vertical line stack a with ‾ on top plus stack b with ‾ on top plus stack a with ‾ on top cross times stack b with rightwards arrow on top vertical line to the power of 2 end exponent plus vertical line stack a with rightwards arrow on top plus stack b with ‾ on top minus stack a with ‾ on top cross times stack b with ‾ on top vertical line to the power of 2 end exponent$ equals

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.