Question
Use Pascal triangle to expand
The correct answer is: From the triangle, the seventh line would give the coefficients of the expansion of the polynomial . Thus, we have:
ANSWER:
Hint:
Hint:
Pascal's Triangle is a method to know the binomial coefficients of terms of binomial expression (x + y)n, where n can be any positive integer and x,y are real numbers. Pascal Triangle is represented in a triangular form, it is kind of a number pattern in the form of a triangular arrangement.
We are asked to find the binomial expansion of using Pascal’s formula.
Step 1 of 1:
The Pascal’s triangle is given by:
From the triangle, the seventh line would give the coefficients of the expansion of the polynomial.
Thus, we have:
Note:
The expansion of the polynomial can be found using the values of
Related Questions to study
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For the expansion of an expression (x + y)n , we would have n+1 terms. This is something you need to keep in mind.
Use polynomial identities to factor the polynomials or simplify the expressions :
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How is obtained from
How is obtained from
Use Pascal triangle to expand (x + y)6
The expansion of the polynomial (x + y)6 can be found using the values of 6Cr
Use Pascal triangle to expand (x + y)6
The expansion of the polynomial (x + y)6 can be found using the values of 6Cr
Use polynomial identities to multiply the expressions ?
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How can you use polynomial identities to factor polynomials and simplify numerical expressions ?
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Use Pascal triangle to expand
The answer cam also be found by expanding the formula of 5Cr .
Use Pascal triangle to expand
The answer cam also be found by expanding the formula of 5Cr .
Use polynomial identities to multiply the expressions ?
Use polynomial identities to multiply the expressions ?
How can you use polynomial identities to factor polynomials and simplify numerical expressions ?
How can you use polynomial identities to factor polynomials and simplify numerical expressions ?
Use polynomial identities to multiply the expressions ?
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How is ( x + y )n obtained from (x + y)n-1
You could also get the value of from by just multiplying a ( x + y) with .
How is ( x + y )n obtained from (x + y)n-1
You could also get the value of from by just multiplying a ( x + y) with .