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Maths-

General

Easy

Question

What is the special case when SSA condition works to
prove the triangle congruence? What do the sides and the angle represent
that case?

The correct answer is: Both the corresponding sides and angles of these two triangles must be the same.

Complete step by step solution:
SSA congruence rule works when 2 sides and an angle not included between them
are respectively equal to 2 sides and an angle of the other then two triangles are
equal.
Both the corresponding sides and angles of these two triangles must be the same

Related Questions to study

If two sides and the included angle of one triangle are
congruent to two sides and the included angle of a second triangle, then the
two triangles are congruent by

If two sides and the included angle of one triangle are
congruent to two sides and the included angle of a second triangle, then the
two triangles are congruent by

In $straight triangle ABC comma space straight angle straight A plus straight angle straight B equals 70 to the power of ring operator$ and $straight angle straight B plus straight angle straight C equals 135 to the power of ring operator$ . Hence find the measure of each angle

In $straight triangle ABC comma space straight angle straight A plus straight angle straight B equals 70 to the power of ring operator$ and $straight angle straight B plus straight angle straight C equals 135 to the power of ring operator$ . Hence find the measure of each angle

Benjamin fills his car with 50 litres of petrol. How much does it cost him if petrol is selling at 94.6pence per litre?

Benjamin fills his car with 50 litres of petrol. How much does it cost him if petrol is selling at 94.6pence per litre?

parallel

Prove that △ CAB ≅△ CAD

Prove that △ CAB ≅△ CAD

$AD comma BE comma CF text are the altitudes of a triangle end text ABC text . Prove that end text BD squared plus EC squared plus AF squared equals DC squared plus EA squared plus FB squared$

$AD comma BE comma CF text are the altitudes of a triangle end text ABC text . Prove that end text BD squared plus EC squared plus AF squared equals DC squared plus EA squared plus FB squared$

Write the following in expanded fractional form :
d) 0.00016

Write the following in expanded fractional form :
d) 0.00016

parallel

In the kite shown, what additional information is required to
prove that △ CAB ≅△ CAD ?

In the kite shown, what additional information is required to
prove that △ CAB ≅△ CAD ?

In $straight triangle XYZ comma straight angle YXZ equals 62 to the power of ring operator text and end text straight angle XYZ equals 54 to the power of ring operator$ and $straight angle XYZ equals 54 to the power of ring operator$ . If YO and ZO are bisectors of $straight angle X Y Z$ and $straight angle X Z Y$ respectively, find $straight angle OZY$ and $straight angle YOZ$ .

In $straight triangle XYZ comma straight angle YXZ equals 62 to the power of ring operator text and end text straight angle XYZ equals 54 to the power of ring operator$ and $straight angle XYZ equals 54 to the power of ring operator$ . If YO and ZO are bisectors of $straight angle X Y Z$ and $straight angle X Z Y$ respectively, find $straight angle OZY$ and $straight angle YOZ$ .

Write the following in expanded fractional form :
c) 4.00524

Write the following in expanded fractional form :
c) 4.00524

parallel

Write the following in expanded fractional form :
b) 2.0504

Write the following in expanded fractional form :
b) 2.0504

Write the following in expanded fractional form :
a) 2.555

Write the following in expanded fractional form :
a) 2.555

$A B C D text is a rectangle. end text D E text is perpendicular from end text D text to end text A C text . Prove that end text A D squared equals A E. A C$

$A B C D text is a rectangle. end text D E text is perpendicular from end text D text to end text A C text . Prove that end text A D squared equals A E. A C$

parallel

In the given picture, if AB = FE, BC = ED, $AB perpendicular BD$ and $FE perpendicular EC$ , then prove that AD = FC.

In the given picture, if AB = FE, BC = ED, $AB perpendicular BD$ and $FE perpendicular EC$ , then prove that AD = FC.

Prove that: ∠ABM ≅ ∠DCM

Prove that: ∠ABM ≅ ∠DCM

Prove that UZ = YZ

Prove that UZ = YZ

parallel

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