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Maths-

General

Easy

Question

$fraction numerator x squared minus 1 over denominator x minus 1 end fraction equals negative 2$
What are all values of that satisfy the equation above?

-3
0
1
-3 and -1

hint Hint:

Hint:

A quadratic equation can be defined as a polynomial equation with second degree

The correct answer is: -3

Explanation:
We have given an equation $fraction numerator x squared minus 1 over denominator x minus 1 end fraction equals negative 2$
We have to find the value of x , that satisfies the given, equation.
We will first do cross multiplication and then solve the equation.
Step 1 of 1:
The given expression is $fraction numerator x squared minus 1 over denominator x minus 1 end fraction equals negative 2$
On cross multiplication, we will get
$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell x squared minus 1 equals negative 2 left parenthesis x minus 1 right parenthesis end cell row cell x squared minus 1 equals negative 2 x plus 2 end cell row cell x squared minus 1 plus 2 x minus 2 equals 0 end cell row cell x squared plus 2 x minus 3 equals 0 end cell end table$
Step 2 of 2:
Using splitting the middle term we will solve the above quadratic equation
$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell x squared plus 2 x minus 3 equals 0 end cell row cell x squared plus 3 x minus x minus 3 equals 0 end cell row cell x left parenthesis x plus 3 right parenthesis minus 1 left parenthesis x plus 3 right parenthesis equals 0 end cell row cell left parenthesis x minus 1 right parenthesis left parenthesis x plus 3 right parenthesis equals 0 end cell row cell text So, end text end cell row cell x equals 1 end cell row cell x equals negative 3 end cell end table$
x= 1 is not possible because it makes the given expression $fraction numerator x squared minus 1 over denominator x minus 1 end fraction equals negative 2$ undefined
So, x=- 3 is the solution.
Hence, Option A is correct.

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