Key Concepts
- Understand about reflection.
- Graph a reflection in horizontal and vertical lines.
- Graph a reflection y = x
- Coordinate rules of reflection
- Graph a reflection y = –x
Graphical Reflections
Introduction
- What transformation is shown in the below image?
Answer:
Reflection along Horizontal line
- What transformation is shown in the below image?
Answer:
Reflection along Horizontal line
- Which image shows reflection transformation?
Answer: c
Reflection
A reflection is a transformation that uses a line to reflect an image, which is similar to a mirror. This mirror line is called the reflection line or line of reflection.
A reflection in a line m maps every point Q in the plane to a point Q’, so that for each point one of the following properties is true:
- If Q is not on n, then n is the perpendicular bisector of QQ’−QQ′- , or
- If Q is on n, then Q = Q’.
Graph reflections along horizontal and vertical lines
Let us understand this concept with the help of an examples.
Example 1:
The vertices of ∆ABC are A (3, 5), B (2, 2), and C (5, 4). Graph the reflection of ∆ABC, in the line n: x = 3
Solution:
Point A is on the n, so its reflection A’ is also on the n at A’ (3, 5)
Point B is 1 unit left to the n, so its reflection is 1 unit to the right of n at B’ (4, 2)
Point C is 2 units right to n, so its reflection is 2 units to the right of n at C’ (1, 4).
Example 2:
The vertices of ∆ABC are A (3, 5), B (2, 2), and C (5, 4). Graph the reflection of ΔABC, in the line m: y = 2
Solution:
Point A is 3 units above m, so its reflection is 3 units below m at (3, -1)
Point B is on the m, so its reflection B’ is on m.
Point C is 2 units above m, so its reflection is 2 units to the below m at C’ (5, 0).
Graph a reflection in y = x
Let us understand this concept with the help of an example:
Example 1:
The endpoints of A are A (–1, 2) and B (1, 2). Reflect the segment in the line y = x. Graph the segment and its image.
Solution:
The slope of y = x is 1. The segment from A to its image, AA′-
is perpendicular to the line of reflection y = x, so the slope of AA′- will be –1.
From A, move 1.5 units right and 1.5 units down to y = x. From that point, move 1.5 units right and 1.5 units down to locate A’ (3, –1).
The slope of BB′- will also be –1. From B, move 0.5 units right and 0.5 units down to y = x. Then move 0.5 units right and 0.5 units down to locate B’ (2, 1).
Coordinate rules for reflection:
- If (a, b) is reflected in the x-axis, its image is the point (a, –b).
- If (a, b) is reflected in the y-axis, its image is the point (–a, b).
- If (a, b) is reflected in the line y = x, its image is the point (b, a).
- If (a, b) is reflected in the line y = –x, its image is the point (–b, –a).
Graph reflection for y = -x
Let us understand this concept with the help of an example:
Example 1:
Reflect AB- in the line y = –x. Graph AB- and its image. A (–1, 2) and B (1, 2).
Solution:
Use the coordinate rule for reflecting in y = –x
(a, b) → (–b, –a)
A (–1, 2) → (–2, 1)
B (1, 2) → (–2, –1)
Example 2:
Reflect AB- in the line y = –x. Graph AB and its image. A (–3, 3) and B (–8, 2).
Solution:
Use the coordinate rule for reflecting in y = –x
(a, b) → (–b, –a)
A (–3, 2) → (–2, 3)
B (–8, 2) → (–2, 8)
Examples:
1. Reflect ∆ABC are A (–3, 2), B (–4, 5), and C (–1, 6) in the line y = 3. Graph ΔABC and its image
Solution:
Point A is 1 unit below y, so its reflection is 1 unit above y at
A’ (–3, 4)
Point B is 2 units above y, so its reflection is 2 units below y at
B (–4, 1)
Point C is 3 units above y, so its reflection is 3 units to the below y at C’ (–1, 0).
2. The endpoints of PQ−PQ- are P (4, –2) and Q(9, –2). Reflect the segment in the line y = x. Graph the segment and its image.
Solution:
If (a, b) is reflected in the line y = x, its image is the point (b, a).
(a, b) → (b, a)
P (4, –2) → (–2,4)
Q (9, –2) → (–2,9)
Exercise
- The vertices of ΔABC are A (3, 5), B (2, 2), and C (5, 4). Graph the reflection of ΔABC, in the line n: y =4
- The vertices of ΔABC are A (3, 5), B (2, 2), and C (5, 4). Graph the reflection of ΔABC, in the line n: x =2
- Graph ΔABC with vertices A (1, 3), B (4, 4), and C (3, 1). Reflect ΔABC in the line y = –x. Graph image.
Graph ΔABC with vertices A (1, 3), B (4, 4), and C (3, 1)
Reflect ΔABC in the line y = x. Graph image.
The vertices of ΔABC are A (3, 5), B (2, 2), and C (5, 4). Graph the reflection of ΔABC, in the line m: y = 2 Graph the reflection of the polygon in the given line.
- Graph the reflection of the polygon in the given line.
- Graph the reflection of the polygon in the given line.
- Graph the reflection of the polygon in the given line.
- What is the line of reflection for ABC and its image?
a. y= 0 b. y = –x c. x=1 d. y=x
Concept Map
What we have learned
- Understand about reflection.
- Graph a reflection in horizontal and vertical lines.
- Graph a reflection y = x
- Coordinate rules of reflection
- Graph a reflection y = –x
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